Which is the completely factored form of 4x2 28x 49?
The completely factored form of 4x2 + 28x + 49 is (2x + 7)(2x + 7).
Answer. = > 4(x - 2)(x + 9). Hope this helps!
The correct factored form of the given equation 4x2 - 25 = 0 is (2x + 5) (2x - 5).
The answer is (4x2−9)=(2x−3)(2x+3) .
x2+14x+49=(x)2+2×x×7+(7)2=(x+7)2 Ans.
What is the GCF of 28 and 42? The GCF of 28 and 42 is 14. To calculate the greatest common factor (GCF) of 28 and 42, we need to factor each number (factors of 28 = 1, 2, 4, 7, 14, 28; factors of 42 = 1, 2, 3, 6, 7, 14, 21, 42) and choose the greatest factor that exactly divides both 28 and 42, i.e., 14.
Summary: The factor of f(x) = 4x3 + 11x2 - 75x + 18 is (x - 3).
Therefore, 4 x 2 - 8 x + 4 can be factorised as ( 2 x - 2 ) 2 .
2x4−32=2(x+2)(x−2)(x2+4)
Hence, 4, x and x2 are factors of 4x2.
What is 4x 2 4x 1 in factored form?
⇒4x2+4x+1=(2x)2+2×2x+12=(2x+1)2.
The completely factored form of x4 + 8x2 - 9 is (x + 3i)(x - 3i)(x + 1)(x - 1).
What is the completely factored form of f(x) = 6x3 - 13x2 - 4x + 15? Summary: The completely factored form of f(x) = 6x3 - 13x2 - 4x + 15 is (x + 1)(2x - 3)(3x - 5).
A fully factored form means the given number or polynomial is expressed as a product of the simplest possible form. For example, if we write 12y2−27=3(4y2−9) 12 y 2 − 27 = 3 ( 4 y 2 − 9 ) , then it is not considered as fully factored form as (4y2−9) ( 4 y 2 − 9 ) can be factored further.
We say that a polynomial is factored completely when we can't factor it any more.
- Move all terms to one side of the equation, usually the left, using addition or subtraction.
- Factor the equation completely.
- Set each factor equal to zero, and solve.
- List each solution from Step 3 as a solution to the original equation.
Therefore, the factors of x2+6x+9 are (x+3)(x+3).
Solution: The GCF of 49 and 28 is 7.
Factors of 28 are 1, 2, 4, 7, 14, and 28. The factorization method is used to find the factors of the number 28.
Solution: The GCF of 28 and 24 is 4.
What are the factors of x3 4x2 11x 30?
Detailed Solution
∴ (x + 2), (x - 3) and (x + 5) are the factors of x3 + 4x2 - 11x - 30.
How many zeros does the function f(x) = 7x13 - 12x9 + 16x5 - 23x + 42 have? Summary: The function f(x) = 7x13 - 12x9 + 16x5 - 23x + 42 will have 13 zeroes.
2x - 7, 2x + 7, 3x - 7, 3x + 7. Solution: Given: Polynomial function is f(x) = 6x4 - 21x3 - 4x2 + 24x - 35. Therefore, the factor of the polynomial is (2x - 7).
Therefore 3x2−4x−4=(3x+2)(x−2)
FAQs on GCF of 8 and 36
The GCF of 8 and 36 is 4. To calculate the greatest common factor (GCF) of 8 and 36, we need to factor each number (factors of 8 = 1, 2, 4, 8; factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36) and choose the greatest factor that exactly divides both 8 and 36, i.e., 4.
4x2−9y2=(2x)2−(3y)2=(2x+3y)(2x3y) {∵ a2−b2=(a+b)(a−b)}
Hence, one of the factor of 2x4+1−3x2 is 2x2−1.
The factors of 32 are 1, 2, 4, 8, 16, and 32, while the factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72. We can see that there are four common factors.
Factors of 32 = 1, 2, 4, 8, 16, and 32.
The expression 4x2, which is read as four times two, is an example of a multiplication expression.
How do you factor 4x 2 28X 3?
- Given: 4X²+28X³
- To Find: Factors.
- Solution: Factorization is finding factors which when multiplied together results in the original number. ...
- Prime Factorize 4. 4 = 2 × 2.
- Factorize X² X² = X × X.
- Prime Factorize 28. 28 = 2 × 2 × 7.
- Factorize X³ X³ = X × X × X.
- Taking common Factors in 4X²+28X³
The sum of two squares cannot be factored. Explanation: This expression can be described as the Sum of Two Squares. 4x2+25 It cannot be factored with Real numbers Only ...
This means that 12x3−4x2=4x2(3x−1)
The expression 4x² - 10x + 4 can be factorised into 2 (x - 2) (2x - 1). The expression 4x² - 10x + 4 can be written as 4x² - 8x - 2x + 4, by splitting - 10x into - 8x and - 2x.
Summary: The completely factored form of 3x5 - 7x4 + 6x2 - 14x is x(x3 + 2)(3x - 7) = 0.
- x4−8x2+16.
- =(x2)2−8(x2)+16.
- =u2−8u+16.
Factorise the following : 9x² - 12x + 4
Therefore, the factors of 9x² - 12x + 4 are (3x - 2)(3x - 2).
The completely factored form of f(x) = x3 - 2x2 - 5x + 6 is (x - 1)(x + 2) and (x - 3).
Hence the factorized form of the polynomial 6 x 2 + 17 x + 5 is ( 3 x + 1 ) ( 2 x + 5 ) .
The completely factored form of 12xy - 9x - 8y + 6 is (3x - 2)(4y - 3).
How do you factor 4x 2 20x 96?
Therefore 4x2+20x−96=4(x+8)(x−3)
4x 2 + 12x + 9 is a perfect square trinomial. 4x 2 + 12x + 9 = (2x) 2 + 2(2x)(3) + (3) 2 Write as a2 + 2ab + b2 .
How do I factor X^2-49? The given algebraic expression, a quadratic binomial, x² - 49 = x² - 7² , falls into the pattern of the "Difference of Two Squares": a² - b² = (a + b)(a - b), where, in this case, a = x and b = 7. x² - 7² = (x + 7)(x - 7) is the original algebraic expression, x² - 49, factored.
Hence, x2−4x−21=(x−7)(x+3)
Therefore, the factors of 49 are 1, 7, and 49 and the factor pairs for 49 are (1, 49), (7 ,7), and (49 ,1).
Thus, the factors of 49 are 1, 7 and 49.
Required factor, =>(3x+7)(3x+7)
Summary: The completely factored form of x4 + 8x2 - 9 is (x + 3i)(x - 3i)(x + 1)(x - 1).
Therefore, the factors of 9x² - 12x + 4 are (3x - 2)(3x - 2).
Hence, Required Factor of x²-4x-5 is (x+1)(x-5).
What is the complete factored form of x2 6x 9?
∴ The factors of x2+6x+9 are (x+3) and (x+3).
Therefore, 4 x 2 - 8 x + 4 can be factorised as ( 2 x - 2 ) 2 .
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